1 Methylimidazole 5 Carboxylic Acid
quinoline thiophene imidazole thiazole

1-Methylimidazole-5-carboxylic acid

    Specifications

    HS Code

    725154

    Name 1-Methylimidazole-5-carboxylic acid
    Molecular Formula C5H6N2O2
    Molar Mass 126.11 g/mol
    Appearance Solid (usually white or off - white)
    Melting Point 179 - 181 °C
    Solubility In Water Moderately soluble
    Pka Around 4.5 (approximate value for the carboxylic acid group)
    Boiling Point Decomposes before boiling
    Odor Odorless (usually)

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    General Information
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    Frequently Asked Questions

    As a leading 1-Methylimidazole-5-carboxylic acid supplier, we deliver high-quality products across diverse grades to meet evolving needs, empowering global customers with safe, efficient, and compliant chemical solutions.

    What is the chemistry of 1-Methylimidazole-5-carboxylic acid?
    1-Methylimidazole-5-carboxylic acid, this is an organic compound. It is active, both acidic and basic. Because it contains a carboxyl group, it is acidic and can react with bases to form salts. This carboxyl group can participate in many esterification reactions. Under suitable conditions, it is catalyzed by concentrated sulfuric acid with alcohols to form corresponding esters. This reaction often requires heating to promote the forward reaction.
    And because its imidazole ring contains nitrogen atoms and has lone pairs of electrons, it is alkaline and can react with acids to form salts. The compound also has a certain coordination ability. The nitrogen atom of the imidazole ring can be used as a ligand to coordinate with metal ions to form complexes. It is widely used in the field of catalysis and can be used as a ligand for metal catalysts to enhance catalyst activity and selectivity.
    In the field of organic synthesis, 1-methylimidazole-5-carboxylic acid is used as a key intermediate to construct complex organic molecular structures. Due to its unique structure and properties, it can participate in a variety of reaction types, providing an effective way for the synthesis of specific functional organic compounds. In pharmaceutical chemistry, or because its structural properties are closely related to biological activity, or participate in the design and synthesis of drug molecules to develop new drugs. Its diverse chemical reactivity and potential biological activity make it significant for research in chemistry and related fields.
    What are the main uses of 1-Methylimidazole-5-carboxylic acid?
    1-Methylimidazole-5-carboxylic acid is useful in various fields.
    First, in the field of pharmaceutical and chemical industry, this is a key intermediate. It can be used through a series of chemical reactions to produce various bioactive compounds. Doctors often use it as a basis to synthesize new drugs, such as antibacterial, antiviral and anti-tumor drugs. Due to the unique structure of 1-methylimidazole-5-carboxylic acid, it can be combined with specific targets in the body to exert pharmacological effects and help in the treatment and prevention of diseases.
    Second, in materials science, it also has its function. Can participate in the preparation of polymer materials with special properties. This monomer can be polymerized with other compounds to obtain polymers with specific functions, such as materials that are adsorbent or responsive to specific substances. Such materials have great application potential in environmental monitoring, material separation, etc., which can efficiently separate mixtures, or respond and detect specific pollutants in the environment.
    Third, in the field of organic synthesis, 1-methylimidazole-5-carboxylic acid is a commonly used synthetic block. Organic chemists design and synthesize many complex organic molecules based on their structural characteristics. Its carboxyl and methylimidazole groups can participate in different types of reactions, such as esterification, amidation, and cyclization, respectively, thereby constructing diverse organic structures, expanding the types and functions of organic compounds, and contributing to the development of organic synthetic chemistry.
    What is the synthesis method of 1-Methylimidazole-5-carboxylic acid?
    The synthesis of 1-methylimidazole-5-carboxylic acid is a very important topic in the field of chemistry. There are many common methods for synthesizing this compound.
    First, it can be prepared from the corresponding nitrogen-containing heterocyclic compound through a specific substitution reaction. For example, a suitable imidazole derivative is used as the starting material, and methyl and carboxyl groups are introduced under suitable reaction conditions. The reaction reagents need to be carefully selected to make the reaction have good selectivity and yield. For example, select a methylation reagent with moderate activity, and then methylate it with imidazole derivatives in a mild alkaline environment, and then introduce carboxyl groups into the molecule through a carboxylation step. This process requires precise control of many factors such as reaction temperature, time, and reagent dosage.
    Second, the imidazole ring structure can also be constructed by cyclization reaction, and the required substituents can be introduced at the same time. First, a chain compound containing a specific functional group is prepared. Under the action of a suitable catalyst, the imidazole ring is formed by cyclization reaction, and during the reaction process, the structural characteristics of the reactants are cleverly used to precisely introduce methyl and carboxyl groups at the target position. This method requires careful optimization of the type and dosage of catalysts, the pH of the reaction system, and other conditions to promote the efficient progress of cyclization to obtain a high-purity 1-methylimidazole-5-carboxylic acid.
    The key to synthesizing 1-methylimidazole-5-carboxylic acid lies in the precise regulation of each reaction step, the rational optimization of reaction conditions according to different starting materials and reaction paths, and the ideal synthesis effect can be achieved.
    What are the precautions for 1-Methylimidazole-5-carboxylic acid in storage and transportation?
    For 1-methylimidazole-5-carboxylic acid, many matters must be paid attention to during storage and transportation. This is an organic compound with active properties, so when storing, the first choice is the environment. It should be placed in a cool, dry and well-ventilated place away from direct sunlight. Due to light or its decomposition and deterioration, its chemical properties will be damaged.
    Temperature is also critical. Overheating or overcooling are not suitable. Generally, storage at room temperature can keep it stable. However, if the ambient temperature is too high, molecular movement will intensify, or chemical reactions will be triggered; if the temperature is too low, it may cause changes in the form of substances, affecting its use.
    Furthermore, the material of the storage container should not be underestimated. Corrosion-resistant containers are required. The cover is acidic and easy to react with certain materials, such as metal containers or corroded, causing contamination or leakage.
    As for transportation, ensure that the packaging is tight. To prevent vibration and collision from causing damage to the packaging and causing leakage. And the transportation process should also maintain a suitable environment to avoid large fluctuations in temperature and humidity. When handling, the operation must be gentle and must not be treated rudely to prevent damage to the packaging.
    In addition, in view of its chemical properties, transportation and storage should be kept away from fire sources, heat sources and strong oxidants, etc., because it may react violently with these substances, resulting in danger. Only by paying careful attention to all matters can the safety and quality of 1-methylimidazole-5-carboxylic acid be ensured during storage and transportation.
    What is the market price range for 1-Methylimidazole-5-carboxylic acid?
    1-Methylimidazole-5-carboxylic acid, this product is in the market, its price is variable, and there are many reasons. In the past, the amount of goods in the market and the urgency of demand were all related to the price.
    In the past, if the supply was sufficient and buyers were scarce, the price would be cheap, per gram or only a few pennies. However, when the supply was scarce, and the demand was too large, the price would rise, reaching dozens of pennies per gram, even more than a hundred.
    In addition, the price of the raw materials used to make this product changed, which also changed its market value. The price of 1-methylimidazole-5-carboxylic acid also decreases when the raw materials are abundant and cheap, and the production cost decreases; on the contrary, the raw materials are scarce and expensive, the cost is high, and the price in the market must rise.
    Furthermore, whether the process is advanced or not is also a variable of price. As the new technique is released, the production efficiency is greatly increased, the cost is less and the goods are more, and the price is lower or lower; if the process is old-fashioned, the production is limited and the cost is huge, and the price is difficult to lower. To sum up, the market price range from a few words per gram to more than a hundred words, and the market conditions are ever-changing, making it difficult to determine a category.